find the greatest number that divides 113,135,160 leaving 5,3,4 remainders resp.
Answers
Answered by
1
113-5= 108
135-3= 132
160-4= 156
Prime factorisation of 108 = 3³* 2²
132= 2²*3*11
156= 2²*3*13
Greatest number=HCF
= 2*2*3 = 12
135-3= 132
160-4= 156
Prime factorisation of 108 = 3³* 2²
132= 2²*3*11
156= 2²*3*13
Greatest number=HCF
= 2*2*3 = 12
Answered by
1
Hope u like
plz mark me as brainly
plz mark me as brainly
Attachments:
Similar questions