Math, asked by kanikamaitysarma5937, 29 days ago

Find the greatest number that divides 93, 111 and 129 leaving 3 as a remainder in each case.

With easy solution .​

Answers

Answered by ammarmahroof890
2

Answer:

18

Step-by-step explanation:

Since Remainder is 3 in each case, the numbers are

93 - 3 = 90

111 - 3 = 108

129 - 3 = 126

Required number will be HCF of 90, 108 and 126

HCF of 90, 108 and 126, By finding the HCF you will get 18

Hope this helps.

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