Question

Find the greatest number that will divides 248 and 1032 leaving remainder 8

Answer 1

Answer:

Given that the largest number when divides 248 and 1032, the remainder is 8 in each case.

248 - 8 = 240 and 1032 - 8 = 1024 are completely divisible by the required number.

Therefore, it is the HCF of 240 and 1024.

Prime factorization of 240 = 2 * 2 * 2 * 2 * 3 * 5

Prime factorization of 1024 = 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2.

HCF(240,1024) = 2 * 2 * 2 * 2

                         = 16.

Therefore the largest number which divides 248 and 1032 leaving remainder 8 in each case = 16.

Hope this helps!

Answer 2

Answer:

268-8=240

1032-8 =IO24

HCf of 240 and 1024 is 16

So the greatest No. 16