Question

find the greatest number which divides 149 and 101 leaving a remainder of 5

Answer 1

We have to determine the greatest number which divides 149 and 101 which leaves remainder as 5.

Therefore, 149 - 5 = 144

and 101 - 5 = 96

Now, we will find the greatest number by taking the HCF of 144 and 96.

Let us find the factors of 144 and 96.

144 = $2 \times 2 \times 2 \times 2 \times 3 \times 3$

96 = $2 \times 2 \times 2 \times 2 \times 2 \times 3$

HCF = $2 \times 2 \times 2 \times 2 \times 3$

= 48.

Therefore, the greatest number which divides 149 and 101 leaving a remainder of 5 is 48.

Answer 2

48 is the answer you should write this