find the greatest number which when divides 286 and 1250 leaving remainder 10,and 8 respectively
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find the greatest number which when divides 286 and 1250 leaving remainder 10,and 8 respectively.
In this type of question ,first we subtract the remainder from the given number and then we find the HCF of number obtained and the HCF is the answer of that question.
So let's do this,
Given numbers are
=> 286 and 1250.
and their remainders
=> 10 and 8 respectively.
so,
=> 286-10
= 276
and
=> 1250-8
=> 1242
so
Now find HCF
276)1242( 4
.. 1104
__________
...... 138)176(1
............. 138
____________
.. ............ 38)138(2
..................... 114
______________
...................... 24)38(1
.......... ................. 24
________________
............................. 14)24(1
............................... .. 14
___________________
.... ......................... .... 10)14(1
.. .... ......................... ..... 10
_____________________
.... ......................... ......... 4)10(2
.... ......................... ............ 8
______________________
.... ......................... ............ 2)4(2
.... ......................... ................ 4
_______________________
.... ......................... ............ ... 0
hence
HCF=2.
Answered by
3
> 286 and 1250.
and their remainders
10 and 8 respectively.
=> 286-10
= 276
and
=> 1250-8
=> 1242
so
Now find HCF
276)1242( 4
.. 1104
__________
...... 138)176(1
............. 138
____________
.. ............ 38)138(2
..................... 114
______________
...................... 24)38(1
.......... ................. 24
________________
............................. 14)24(1
............................... .. 14
___________________
.... ......................... .... 10)14(1
.. .... ......................... ..... 10
_____________________
.... ......................... ......... 4)10(2
.... ......................... ............ 8
______________________
.... ......................... ............ 2)4(2
.... ......................... ................ 4
_______________________
.... ......................... ............ ... 0
aadityabhukar81:
hello my dear friend
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