Question

Find the hcf and lcm of 60 84 and 108 using fundamental theorem of arithmetic

Answer 1

60=2×2×3×5

84=2×2×3×7

108=2×2×3×3×3

Lcm = 2×2×3×3×3×5×7=3780

Hcf = 2×2×3=12

Answer 2

We have :-

60 = (2² × 3 × 5)

84 = (2² × 3 × 7)

108 = (2² × 3³)

HCF(60,84,108) => (2² × 3) = 12

LCM(60,84,108) :-

= 2² × 3³ × 5 × 7

= 3780