Question

find the hcf of 1624 522 1276

Answer 1

Hiii friend,

Prime factorisation of 1624 = 2 × 2 × 2 × 7 × 29

Prime factorisation of 522 = 2 × 3 × 3 × 29

Prime factorisation of 1276 = 2 × 2 × 29 × 11

HCF of 1624 , 522 , 1276 = 2 × 29 = 58


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Answer 2

Answer:

Step-by-step explanation:

Concept:

The concept of highest common factor will be used to solve this question.

the biggest number or amount that each member of a set of numbers or quantities has as a factor.

Given:

The numbers which are given are $1624,522$ and $1276$ .

To Find:

We have to find the highest common divisior of these $3$ numbers.

Solution:

To get the h.c.f of these number we need to get the prime factorisation of each number.

The prime factorisation of $1624$ is $2 \times 2 \times 2 \times 7 \times 29$

The prime factorisation of $522$ is $2 \times 3 \times 3\times 29$

The prime factorisation of $1276$ is $2 \times 2 \times 29 \times 11$

Among these factorisations only $2$ and $29$ is common from these $3$ numbers.

Therefore the h.c.f of these three numbers is $2 \times 29=58$ .

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