Question

Find the HCF of 180,252nd324 using Euclid division lemma

Answer 1

Step-by-step explanation:

Let, a=324,b=252,c=144

By, Euclid's Division Lemma

a=bq+r

324=252×1+72

252=72×3+36

72=36×2+0

Hence,HCF of 324 and 252 is 36

Now, let, d=36

By,Euclid's Division Lemma

c=dq+r

144=36×4+0

Since, 36 is the common last divisor of a,b,c

Hence, HCF of a,b,c is 36

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