find the HCF of 55 and 210. Express it as a linear combination of 55 and 210, i.e. HCF of 55 and 210 = 210a + 55b, for some A and B
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Answer:
A=1 and B=12
Step-by-step explanation:
- 210=55×3+45
- 55=45×1+10
- 45=10×4+5
- 10=5×2+0
- HCF=5
- 5=45-10×4
- =(210-55×3)-10×4
- =210-55(3)-(55-45×1)×4
- 210-55(3)-55(4)+45(4)
- 210+55(-3)+55(-4)+45(4)
- 210(1)+55(12)
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