find the HCF of 60 and 405 and express it in the form 60q + 405r.
Answers
Answered by
1
Step-by-step explanation:
60 & 405
To find : HCF of 60 and 405
Solution:
HCF of 60 * 405
405 = 60* 6 + 45
60 = 45 * 1 + 15
45 = 15 * 3
15 is the HCF
405 = 60* 6 + 45
putting 45 = 60 - 15
=> 405 = 60* 6 + 60 - 15
=> 405 = 60 * (6 + 1) - 15
=> 15 = 60 * 7 - 405
=> 15 = 60 * 7 + 405 *(-1)
q = 7 & r = - 1
Answered by
5
Answer:
Step-by-step explanation:
Given : 60 & 405
To find : HCF of 60 and 405
Solution:
HCF of 60 * 405
405 = 60* 6 + 45
60 = 45 * 1 + 15
45 = 15 * 3
15 is the HCF
405 = 60* 6 + 45
putting 45 = 60 - 15
405 = 60* 6 + 60 - 15
405 = 60 * (6 + 1) - 15
15 = 60 * 7 - 405
15 = 60 * 7 + 405 *(-1)
q = 7 & r = - 1
Similar questions
Physics,
3 months ago
Art,
3 months ago
Social Sciences,
3 months ago
India Languages,
7 months ago
English,
7 months ago
Social Sciences,
11 months ago
Social Sciences,
11 months ago