Question

find the HCF of 963 and 657 and convert it into linear equation
plz explain step by step

Answer 1

963 =657× 1+306

hence the remainder is not zero we will take a as 657 b as 306

657= 306× 2+45

306= 45× 6+36

45= 36×1+9

36=9×4+0

hence h c f of the numbers is 9

9 =657x + 973y

Answer 2

Hope it helps you...