find the HCF of the following by the short division method: 60,80,100
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Answer:
H.C.F OF 6080100= 20
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2 l60l80l100
2 l30l40l50
5 l15l20l25
3 l3l4l5
4 l1l4l5
5 l1l1l5
60= 2×2×5×3
80=2×2×5×4
100=2×2×5×5
common factors=2×2×5
2×10
20
therefore HCF IS 20
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