Question

find the HCF of the following numbers by prime factorisation method a 26,28​

Answer 1

Step-by-step explanation:

$= > 26 = 13 \times 2 \\ \\ 28 = 7 \times 2 \times 2 \\ \\ = > 28 = 7 \times {2}^{2}$

HCF(26 , 28) = 2

Answer 2

$\huge{\sf{\red{\underline{Question:-}}}}$

Find the HCF of the following numbers by prime factorisation method 26,28.

$\huge{\sf{\blue{\underline{Answer:-}}}}$

• HCF is the Highest Common Factor of two or more numbers.
• We can find HCF by long division method, and by prime factorisation.

Here the numbers are 26 and 28

Prime factors mean factors of a number which are themselves prime numbers.

First split both the numbers into their prime factors:

• 26 = 2 * 13
• 28 = 2 * 7 * 2

Here 2 is prime factor which is common to both 26 and 28

Hence 2 is their HCF.

$\bf{\red{{\huge\boxed{HCF\:=\:2}}}}$