find the hcf of x ^ 4 * y ^ 3 and * x ^ 2 * y
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Answer:
kindly see the answer below...
Step-by-step explanation:
Here, we have to find out the HCF of
so, now
is the HCF of the two no. s
thanks a lot...
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Given :- Mass of boat (M₁) = 40 kg
Mass of doɡ (m₂) = 4 kg
Velocity of doɡ (v₂) = 10m/sec
To Find :- The velocity of the boat (V₁)
Solution :-
By conservation of linear momentum
Momentum of boat = Momentum of dog
M₁V₁ = m₂v₂
40V₁ = 4 × 10
40V₁ = 40
V₁ = 40/40
V₁ = 1m/sec
Hence, option (4) 1m/sec is correct.
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