Question

find the heat needed to convert 10g of ice at -10degree celsius to water at 20 c​

Answer 1

${\huge{\boxed{\mathcal{\red{Answer}}}}}$

Heat energy required = 4620J

${\huge{\boxed{\mathcal{\red{Explanation}}}}}$

The heat energy required to convert 10g of ice at -10°C to 20°C = Heat energy required to convert ice to water + Heat energy required to raise temperature of water from -10/°C to 20°C.

Now , It is given that :-

Latent heat of fusion of ice = 336 × 10^3 J/kg

$= 336 \times 1000 \div 1000 joules/g$

$= 336joule/g$

Specific heat of water = 4200 J /kg/K

$= 4200 \div 1000joules/g/k$

$= 4.2j/g/k$

Now, heat energy required to concert 10g of ice to water = Latent heat of fusion of ice × Mass of ice

$= 336 \times 10 = 3360j$

Heat energy required to convert 10g of water from -10°C to 20°C = Mass of water × Temperature to be raised × Specific heat capacity.

$= 10 \times 30 \times 4.2 = 300 \times 4.2$

$= 1260j$

Now the total net heat energy required to convert 10g of ice at -10°C to 20°C is equals to

$= 3360 + 1260 = 4620joules$

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BY SCIVIBHANSHU

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