Question

Find the height of a triangle whose base is 5 inches and area is 12 square inches.

2 2/5 in.
4 4/5 in.
30 in.

Answer 1

ar∆=1/2 ×b×h

1/2×5×h=12

h=12×2/5

=24/5=4.8 inches

Answer 2

Question :- Find the height of a triangle whose base is 5 inches and area is 12 square inches. ?

Solution :-

Triangle :--- is a plane figure with three straight sides and three angles.

→ Area of ∆ = 1/2 * Base * Height = 1/2* ab* sinC = 1/2 * bc *sinA = 1/2 * ca* sinB = √( s(s-a)(s-b)(s-c) ) [ where s = (a+b+c)/2 ]

given that,

• Base = 5 inches .
• Area = 12 inches² .

then,

→ Area of ∆ABC = (1/2) * Base * Height

→ 12 = (1/2) * 5 * Height

→ 12 * 2 = 5 * Height

→ 24 = 5 * Height

→ Height = (24/5)

→ Height = 4.8 inches. (Ans.)

Learn more :-

In ABC, AD is angle bisector,

angle BAC = 111 and AB+BD=AC find the value of angle ACB=?

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