Question

Find the height of the trapezium the
sum of the lengths of whose bases ie 50cm
and whose area
is 8.500 cm²​

Answer 1

Answer:

Sum of parallel sides = 50 cm.

Given Area = 500 cm².

Here, h = height , a and b are two parallel sides.

Also, area of trapezium = \frac{1}{2} X h X (a+b)Also,areaoftrapezium=

2

1

XhX(a+b)

\begin{gathered}500 = \frac{1}{2} hX(a+b) \\ \\ 500= \frac{1}{2}hX50 \\ \\ \frac{500}{50}= \frac{1}{2} h \\ \\ h= 20\end{gathered}

500=

2

1

hX(a+b)

500=

2

1

hX50

50

500

=

2

1

h

h=20

Hence height of trapezium is 20 cm.

Hope it helps