find the initial velocity of a car which stops in 10 sec after applying brakes at the rate of 2m/s2
Answers
Answered by
10
u = ?
v = 0
t = 10s
a = -2 m/s²
v = u +at
⇒ 0 = u + (-2)×10
⇒ 0 = u - 20
⇒ u = 20 m/s
Initial velocity was 20 m/s
v = 0
t = 10s
a = -2 m/s²
v = u +at
⇒ 0 = u + (-2)×10
⇒ 0 = u - 20
⇒ u = 20 m/s
Initial velocity was 20 m/s
Answered by
28
Heya......!!!
______________________
This question can be easily solved by applying equation of motion .
Given in the question :-
• Final velocity ( v ) = 0
• Time. ( t ) = 10 sec
• Acceleration ( a ) = -2 m/s^2. ( -ve sign indicates retardation .
So , by applying the equation ' v = u + at ' we can take out initial velocity ( u ) .
Putting the values we get -
→ 0 = u - 2×10
→ u = 2 × 10
➡ u = 20 m/s ( initial velocity ) .
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Hope It helps You. ☺
______________________
This question can be easily solved by applying equation of motion .
Given in the question :-
• Final velocity ( v ) = 0
• Time. ( t ) = 10 sec
• Acceleration ( a ) = -2 m/s^2. ( -ve sign indicates retardation .
So , by applying the equation ' v = u + at ' we can take out initial velocity ( u ) .
Putting the values we get -
→ 0 = u - 2×10
→ u = 2 × 10
➡ u = 20 m/s ( initial velocity ) .
---------------------------------------------------
Hope It helps You. ☺
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