Find the integral zeros of the polynomial x^3 + 3x^2 -x -3
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Answer:
x^3+3x^2-x-3
x^2(x+3) -1(x+3)
x^2-1=0 x+3=0
x=1= alfa x=(-3) = bita
sum of zeroes: alfa + bita = -b/a
1+(-3) = -(-3) /1
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