Question

find the interest and the amount on rupees750 in 3 years 4 months at 10% per annum

Answer 1

Answer:

Given P = ₹750

Time (T) = 3. 4/12 = 3.1/3

= 10/3 years

Rate (R) = 10%

∴ Interest (I) = PRT/100 = (750 × 10 × (10/3))/100

= (250 × 10 × 10)/100 = ₹250

∴ Amount (A) = P + I = ₹750 + ₹250 = ₹1000

(ii) Principal (p) = ₹5000

Rate (R) = 8% p.a

Time (T) = 23 December 2011 to 29 July 2012

Dec. Jan. Feb. March April May June July

8 31 29 31 30 31 30 29

Total 219 days = (219/365) Years

∴ Interest = PRT/100 = (5000 × 8 × 219)/(100 × 365)

= 10 × 8 × 3 = ₹240

∴ Amount = P + I = ₹5000 + ₹240 = ₹5240

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Answer 2

Step-by-step explanation:

now period for interest is 3 yrs 4 months

means 4/12=1/3

3+1/3=10/3....

so now

SI=PNR/100

SI=(750*10*10/3)/100

SI=250*10*10/100

SI=25000/100

SI=250