From the top of a tower 36 m high, a body
is dropped and at the same time another
body is projected vertically upward from
the ground. If they meet midway find the
initial velocity of the projected body and
its velocity when the two bodies come together.
1) 5√6 m/s,0
2) 42/√5 m/s,0
3)6√6 m/s,2m/s
4) 8√6 m/s,4.5m/s
Answers
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Acceleration
Distance
Final Velocity
v = u + a*t
Initial Velocity u
m/s
Final Velocity v
m/s
Time t
s
Acceleration a
m/s²
RESET VALUES
ANSWER
Equation to use :
for first body x=
2
1
gt
2
for second body (h−x)=ut−
2
1
gt
2
Now solving,
For A ⇒18=
2
1
gt
2
g
2×18
=t
1
For B ⇒18=ut−
2
1
gt
2
(t=t
1
)
⇒18=u
g
36
−
2
g
×
g
36
⇒36=u
g
36
⇒u=18.78=
5
42
m/s
When they come in contact:
Velocity of B is, v
B
=u−gt =
55
42
−9.8×1.916
v
B
=0 m/s
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Answer:
If they meet midway, find the initial velocity of the projected body and its velocity when the two bodies come together. A. 56 ...
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