Question

Find the largest no that divides 2053 and 967 and leaves a remainder 5 and 7 respectively

Answer 1

it is given that on dividing 2053 by the required number there is a remainder of 5 .this mean that 2053 - 5 = 2048 is exactly divisible by required number . similarly,
967 - 7 = 960
the required number is the largest number satisfying the above property .
therefore ,it is the HCF of 2048 & 960
HCF of 2048 & 960 is 64 
hence required number is 64

Answer 2

your answer is 64 first of all u substact the number 2053 '967 5 and 7 2048 and 960 hcf of this number is 64