Find the largest no that divides both 58 and 85 leaving a remainder of 4 in each case
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16
largest no. that could divide 58 and 85 and leave a remainder 4 is:
HCF(58-4) and HCF(85-4)
=HCF(54 and 81)=27
Therefore, the largest number that divides the both number is 27.
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HCF(58-4) and HCF(85-4)
=HCF(54 and 81)=27
Therefore, the largest number that divides the both number is 27.
Mark it as brainliest.
ChristyJacob123:
Plz Mark my answer as brainliest
Answered by
5
Given:
Two numbers 58 and 85
To Find:
The largest no that divides both 58 and 85 leaving a remainder of 4 in each case
Solution:
To find the number which will leave the remainder 4
We have to subtract 4 from both the numbers
58-4 = 54
85-4 = 81
Now, we have to find the H.C.F (Highest Common Factor) of both the numbers
Let us factorize both the numbers
54 = 2×3×3×3
81 = 3×3×3×3×3×3
H.C.F = 3×3×3
= 27
Hence, the largest no that divides both 58 and 85 leaving a remainder of 4 is 27.
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