Math, asked by Pratiksa, 1 year ago

Find the largest no. That will divide the 398,436,542 leaving remainder 7,11,15 respectively

Answers

Answered by Love11111
24
On dividing 398 by the required number, there is a remainder of 7. This means that 398 7 = 391 is exactly divisible by the required number. Similarly, 436 -11 = 425 and 542 15 = 527 are exactly divisible by the required number.
The HCF of two positive integers is the largest positive integer that divides both the integers.
So, the required number will be the HCF of 391, 425 and 527. And that can be found by using Euclids division algorithm.
425 = 391 x 1 + 34
391 = 34 x 11 + 17
34 = 17 x 2 + 0
Thus, HCF = 17
Hence, the required number is 17
Hope it helps



Pratiksa: Tnkuuuu
Love11111: My pleasure
Answered by tejal9547
3

Answer:

Step-by-step explanation:

Find hcf of the subtracted nos from real on

HCF =17

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