find the largest number that divides 10 and14 leaving a remainder of 2
Answers
Answer:
4
Step-by-step explanation:
10+2 = 12
14+2 = 16
Largest number that divides 10 and 14 leaving remainder 2 = HCF of 12 and 16.
12 = 2×2×3
16 = 2×2×2×2
HCF = 2×2 = 4
Hence, 4 is the answer.
Given: A number divides 10 and 14 leaving a remainder of 2.
To find: The largest possible value of this number
Solution: To solve this problem, we need to make use of Highest Common Factor (HCF).
In order to do that, first we add the remainder to the given numbers.
10 + 2 = 12
14 + 2 = 16
Now we need to find the HCF of these two numbers to get the largest number that divides them.
Let us break down the numbers into prime factors.
12 = 2² × 3
16 = 2⁴
Hence, the HCF of 12 and 16 is 2² = 4.
Therefore, the largest number that divides 10 and 14 leaving a remainder of 2 is 4.