Question

Find the largest number which divides 615 and 963 leaving reminder 6 in each case.

Answer 1

Heya !!!

This is your answer....

Given numbers:-
615 and 963 leaving remainder of 6 in each case.

So,
615 -6 = 609
963 -6 = 957.

Now HCF of 609 and 957 by prime factorisation method ....

609 = 3×7×29
957 = 3×11×29

Therefore, HCF = 3×29 = 87.

Hence, the required number is 87.

Hope it helps uh....