Question

Find the largest number which divides 615 and 963 leaving remainder 6 in each case . I want step by step explanation friends.​

Answer 1

Answer:

87

Step-by-step explanation:

To find the largest number which divides 615 and 963 leaving remainder 6 in each case i.e HCF.

consider HCF be x

in order to make 615 and 963 completely divisible by x , we need to deduct the remainder 6 from both the cases

615 -6= 609

963 -6= 957

prime factorization of both numbers

615= 3×3×29

957= 3×11×29

X= 3×28

x= 87

largest number which divides 615 and 963 leaving remainder 6 in each case is is 87.

I hope it will help you

Answer 2

Step-by-step explanation:

615-6 = 609

963-6 = 957

957 = 609 X 1 + 348

609 = 348 X 1 + 261

384 = 261 X 1 + 87

261 = 87 X 3 + 0

The largest no. which divides 615 and 963 leaving remainder 6 in each case is 87.