find the largest number which exactly divides 280 and 1245 leaving remainder 4 and 3
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280-4=276
1245-3=1242
largest number =HCF(276,1242)
1242=2×3×3×3×23
276=2×3×2×23
HCF(1242,276)=2×3×23
=138
1245-3=1242
largest number =HCF(276,1242)
1242=2×3×3×3×23
276=2×3×2×23
HCF(1242,276)=2×3×23
=138
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