Question

Find the largest number which when divided 220,328 and436
leaves 4 as a remainder in each case

Answer 1

Answer:108

Step-by-step explanation:

At first subtract 4 from all of the given number

Doing so we get

220-4 = 216

328-4 = 324

436-4 = 432

Now for the largest number which divides it we have to find HCF and the required HCF is the answer

So we can do it so by division method

HCF of 216 and 324

216) 324( 1

- 216

-------------------

108) 216( 2

- 216

-------------------------

XXX

So HCF of 216 & 324 = 108

Now find HCF of 108 & 432

108) 432(4

- 432

--------------------

XXX

So the HCF of 216 & 324 & 432 is 108

Answer is 108

Thanks

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Answer 2

Answer:

Step-by-step explanation:

108