Find the least 5 digit number which is exactly divisible by 20, 25, 30
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- lcm of 20,25,30 is 300
- smallest 5 digit number is 10000
- therefore we will divide 10000 by 300
- we get remainder 100
- now our question is 100 should be increased by how much so that the resulting number is divisible by 300
- since 300-100 =200
- therefore 10000+200 =10200 is the least 5 digit number that exactly divisible by 20, 25, 30
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