Find the least number of 6 digits, which being divided by 18, 21, 24 and 36 will have no remainder
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The least number which is exactly divisible by each given number is their L.C.M.
Required number L.C.M. of 12, 15, 18, 24 and 36.
∴ L.C.M. = least required number
= 2 × 2 × 3 × 3 × 5 × 2 = 360
Hence, the least required number = 360
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Find the least number of 6 digits, which being divided by 18, 21, 24 and 36 will have no remainder
ANS:100296
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