Question

Find the least number of five digits which is exactly divisible by 32,36and 45.

Answer 1

32= 4 ...16..32
36= 4,,6,,9,,18,,36
45=5,15,45

Answer 2

$Heya \: mate, \\ \\ Here \: is \: your \: solution - \\ \\ To \: have \: a \: number \: which \: is \\ exactly \: divisible \: by \: 32 , \: 36 \\ and \: 45 \: we \: must \: take \: LCM \\ of \: them. \\ \\ So, \\ LCM \: of \: 32 , \: 36 \: and \: 45 \: = \: 1440. \\ \\ 1140 \: is \: a \: four \: digit \: number \\ and \: a \: 5 \: digit \: number \: which \: \\ is \: exactly \: divisible \: by \: \\ 32 \: 36 \: and \: 45 \: must \: be \: divisible \: by \\ 1440 \: so \: in \: other \: words \: we \\ can \: say \: it \: must \: be \: a \\ multiple \: of \: 1440 . \\ so \: let's \: find \: the \: smallest \: five \\ digit \: multiple \: of \: 1440. \\ \\ Hence, \\ 1140 \times 7 = 10080 \: \: (answer)$
#Kevin

Hope it helps you.