find the least number that is divisible by all the numbers between 1 and 10( both inclusive)
Answers
2520 is the smallest number
Answer:
2520
Step-by-step explanation:
The least number which is divisible by all the numbers betweem 1 and 10 = L.C.M of all numbers between 1 and 10 = 2520 2.�Let us three consecutive� integers be, n, n + 1 and n + 2. Whenever a number is divided by 3 the remainder obtained is either 0 or 1 or 2. let n = 3p or 3p + 1 or 3p + 2, where p is some integer. If n = 3p, then n is divisible by 3. If n = 3p + 1, then n + 2 = 3p + 1 + 2 = 3p + 3 = 3(p + 1) is divisible by 3. If n = 3p + 2, then n + 1 = 3p + 2 + 1 = 3p + 3 = 3(p + 1) is divisible by 3. So that n, n + 1 and n + 2 is always divisible by 3. ⇒ n (n + 1) (n + 2) is divisible by 3. � Similarly, whenever a number is divided 2 we will get the remainder is 0 or 1. ∴ n = 2q or 2q + 1, where q is some integer. If n = 2q, then n and n + 2 = 2q + 2 = 2(q + 1) are divisible by 2. If n = 2q + 1, then n + 1 = 2q + 1 + 1 = 2q + 2 = 2 (q + 1) is divisible by 2. So that n, n + 1 and n + 2 is always divisible by 2. ⇒ n (n + 1) (n + 2) is divisible by 2. � But n (n + 1) (n + 2) is divisible by 2 and 3. � ∴ n (n + 1) (n + 2) is divisible by 6