Find the least number which on being added 25 to it , is exactly divisible by 32,36,48,96
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The smallest number divisible by all of 32,36,48,96 is 288 because 288 is the LCM of the given numbers . so our required answer is 288–23=265.\
aaenterprise261:
Why we minus 23 the number 25 na
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