find the least number which wgen increased by 3 is divisible by 36, 40, 64
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Answered by
62
Solution :-
To find the least number which when increased by 3 is divisible by 36, 40 and 64, we first have to find the L.C.M. of 36, 40 and 64
Prime Factorization of numbers
36 = 2*2*3*3
40 = 2*2*2*5
64 = 2*2*2*2*2*2
L.C.M. of 36, 40 and 64 = 2*2*2*2*2*2*3*3*5
= 2880
So, 2880 is the number which is already increased by 3.
Therefore, the number we need is 3 less than 2880
So, the required number is 2880 - 3 = 2877
Hence, 2877 is the least number which when increased by 3 is divisible by 36, 40 and 64.
To find the least number which when increased by 3 is divisible by 36, 40 and 64, we first have to find the L.C.M. of 36, 40 and 64
Prime Factorization of numbers
36 = 2*2*3*3
40 = 2*2*2*5
64 = 2*2*2*2*2*2
L.C.M. of 36, 40 and 64 = 2*2*2*2*2*2*3*3*5
= 2880
So, 2880 is the number which is already increased by 3.
Therefore, the number we need is 3 less than 2880
So, the required number is 2880 - 3 = 2877
Hence, 2877 is the least number which when increased by 3 is divisible by 36, 40 and 64.
Answered by
5
Answer:
2877
Step-by-step explanation:
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