Math, asked by kyashvant848, 1 month ago

Find the least number which when divided by 12, 16, 24 and 36 leaves a remainder 7 in

each case?​

Answers

Answered by as7803617
4

Answer:

Hence the smallest number that when divided by 12 16 24 and 36 leaves a remainder 7 is 151.

Answered by RomanticBabe
7

Answer:

 \sf \orange{12 = 2 \times 2 \times 3}

 \sf \orange{16 = 2 \times 2 \times 2 \times 2}

 \sf \orange{24 = 2 \times 2 \times 2 \times 3}

 \sf \orange{36 = 2 \times 2 \times 3 \times 3}

 {\sf{\pink{LCM(12,16,24,36) = 2 \times 2 \times 2 \times 2 \times 3 \times 3 = 144}}}

 \sf \blue{Hence \:  144 +7 = 151  \: is \:  divided \:  by} \\ {\sf{\blue{12,16,24,36  \:leaves \:  the  \: reminder  \: 7.}}}

 \\  \\

 \mathfrak \red{@RomanticBabe}

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