Question

Find the least number which when divided by 12, 16, 24 and 36 leaves a remainder 7 in

each case?​

Answer 1

Answer:

Hence the smallest number that when divided by 12 16 24 and 36 leaves a remainder 7 is 151.

Answer 2

Answer:

$\sf \orange{12 = 2 \times 2 \times 3}$

$\sf \orange{16 = 2 \times 2 \times 2 \times 2}$

$\sf \orange{24 = 2 \times 2 \times 2 \times 3}$

$\sf \orange{36 = 2 \times 2 \times 3 \times 3}$

${\sf{\pink{LCM(12,16,24,36) = 2 \times 2 \times 2 \times 2 \times 3 \times 3 = 144}}}$

$\sf \blue{Hence \: 144 +7 = 151 \: is \: divided \: by} \\ {\sf{\blue{12,16,24,36 \:leaves \: the \: reminder \: 7.}}}$

$\mathfrak \red{@RomanticBabe}$