Question

Find the least number which when divided by 12, 16 and 18 leaves 5 as remainder in each case. *

Answer 1

Answer: 2

Step-by-step explanation:

Answer 2

AnswEr :

149

$\bf{\underline{\underline{\bf{Given\::}}}}}$

When divided by 12,16 and 18 leaves 5 as remainder in each case.

$\bf{\underline{\underline{\bf{To\:find\::}}}}}$

The least number.

$\bf{\underline{\underline{\bf{Explanation\::}}}}}$

Taking L.C.M of 12,16 and 18 :

$\begin{array}{r|l} 2& 12,16,18\\ \cline{2-2} 2& 6,8,9\\ \cline{2-2} 2& 3,4,9\\ \cline{2-2} 2& 3,2,9 \\ \cline{2-2} 3& 3,1,9\\ \cline{2-2}3& 1,1,3\\ \cline{2-2} &1 ,1,1\end{array}$

L.C.M are = 2 × 2  × 2 × 2 × 3 × 3 = 144.

Now;

The least number required :

Number = 144 + 5

Number = 149.