Question

Find the least number which when divided by 16, 36 and 40 leaves 5 as remainder in each case.​

Answer 1

Answer:

To find the least number which is divisible by 16,36 and 40 and leaves 5 in each case as reminder first we have to subtract 5 from 1636 and 40 .

That is

16-5=11

36-5=31

and 40-5=35

Then we have to find the LCM of the number 11,31 and 35 so LCM of the 3 numbers is 11935

So the answer is 11935.

Answer 2

Answer:

725

Step-by-step explanation:

16 = 2 * 2 * 2 * 2

36 = 2 * 2 * 3 * 3

40 = 2 * 2 * 2 * 5

   LCM = 2*2*2*2*3*3*5 = 720

720 is completely divisible by all, so as to leave a remainder it should be 720 + 5 = 725