Find the least number which when divided by 2540 and 15 leaves a remainder of 7 in each case
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Answered by
3
Heya
Let the number be x
When x is divided by 2540 and 15, it leaves a remainder 7
That means, x-7 is exactly divisible by 2540 and 15
LCM of 2540 and 15 is 7620
The number of 7629+7=7627
Hope it helps
Let the number be x
When x is divided by 2540 and 15, it leaves a remainder 7
That means, x-7 is exactly divisible by 2540 and 15
LCM of 2540 and 15 is 7620
The number of 7629+7=7627
Hope it helps
Answered by
4
Heya !!!
Prime factorisation of 2540 = 2 × 2 × 5 × 127
Prime factorisation of 15 = 3 × 5
LCM of 2540 and 15 = 7620
Required Number= LCM of (2540 and 15) + 7 = 7620 +7 = 7627.
HOPE IT WILL HELP YOU..... ;-)
Prime factorisation of 2540 = 2 × 2 × 5 × 127
Prime factorisation of 15 = 3 × 5
LCM of 2540 and 15 = 7620
Required Number= LCM of (2540 and 15) + 7 = 7620 +7 = 7627.
HOPE IT WILL HELP YOU..... ;-)
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