find the least number which when divided by 8 12 16 leaves 3 as reminder in each case,but when divided by 7,leaves no remainder
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Answered by
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LCM of 8, 12 and 16 = 48
So The nos. which when divided by 12,16 and 8 and leave remainder 3 will be a multiple of 48 + 3
These nos. are 51 ( 48×1 + 3), 99 (48×2 + 3), 147 ( 48×3 +3)... and so on. The least of them which leaves no remainder when divided by 7 is 147.
So the ans. is 147.
So The nos. which when divided by 12,16 and 8 and leave remainder 3 will be a multiple of 48 + 3
These nos. are 51 ( 48×1 + 3), 99 (48×2 + 3), 147 ( 48×3 +3)... and so on. The least of them which leaves no remainder when divided by 7 is 147.
So the ans. is 147.
Answered by
24
Hlo !
147 is the least no. When divided by 8 , 12 , 16 leaves 3 but when when divided by 7 leaves no remainder
147 is the least no. When divided by 8 , 12 , 16 leaves 3 but when when divided by 7 leaves no remainder
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