Find the least square number which is exactly the viable by each of the number 8 12 15 and 20
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Answer: Smallest Square Number exactly divisible by 8,12,15 and 20 is 3600
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step by step:
8=2power3
12=2power2 × 3
15=3×5
20=2power2 × 5
choose the maximum of all the prime exponent
LCM = 2power3×3×5 = 120
Now, 120 = 2power3×3×5
Now, in a perfect square , the exponent of each prime is always even .
So, we will change the exponent of 2 from 3 to 4
and exponent of 3 from 1 to 2 and exponent of 5 from 1 to 2.
Finally we have the number
2power4 × 3power2 × 5power2 =3600
So the required answer is 3600
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