Question

find the length of a chord which is at a distance of 5 cm from the centre of a circle of radius 10 centimetre

Answer 1

I think the answer is 5 but not at all sure. I think that consulting this question to one more person would be good

Answer 2

let ab be chord of circle.
o is center of circle.
om perpendicular to ab
am = mb a perpendicular drawn from center of circle to its chord bisects the chord.
in triangle AOB m angle m = 90°
By pythagoras theorem
${oa}^{2} = {am}^{2} + {mo}^{2} \\ {10}^{2} = am {}^{2} + 5 {}^{2} \\ am {}^{2} = 100 - 25 \\ am {}^{2} = 75 \\ am = \sqrt{75 } \\ am = 5 \sqrt{3}$

ab =am+mb
$5 \sqrt{3} + 5 \sqrt{3 } \\ 10 \sqrt{3}$
length of chord is 10root3