Question

find the length of a diagonal of a square if its side= 6 cm

Answer 1

$length \: of \: the \: diagonal \: = \sqrt{6 {}^{2} + 6 {}^{2} }cm \\ = \sqrt{72} cm \\ = 6 \sqrt{2} cm \\ hope \: it \: helps \: you$

Answer 2

Answer:

Diagonal of a square = 6 $\sqrt{2}$

Step-by-step explanation:

Length of the square is 6 cm.

let the length of square be a

So, a = 6

diagonal of the square = $d = a\sqrt{2}$

diagonal of the square = 6 $\times \sqrt{2}$

Diagonal of a square = 6 $\sqrt{2}$.

If we do this by pythagorean theorem

$h^2 =b^2 + p^2\\d^2 = a^2 + a^2\\d^2 = 6^2 + 6^2 \\d^2 = 36 +36\\d^2 = 72\\d = \sqrt{72}\\ d = 6 \sqrt{2}$