Question

Find the length of a seconds' pendulum at a place
where g = 10 ms? (Take = 3.14).​

Answer 1

Answer:

1.014 m

Step-by-step explanation:

$T = 2\pi \sqrt{l/g}$

T = 2

∴ 2 = 2π√(L/10)

Squaring on both sides

⇒1 = (3.14)²*L/10

⇒L = 10/(3.14)² = 1.014 m

Answer 2

Answer:

Step-by-step explanation:

T=2π  $\sqrt{l/g}$

2 = 2π $\sqrt{l/g}$

Therefore, l = g/$\pi ^{2}$

                    = 10 / $3.14^{2}$

                    = 1.01 m