Question

find the length of a seconds pendulum at a place where g=10ms

Answer 1

see attachment.. .........

Answer 2

T = 2 $\pi$ √l/g
(T of second's pendulum = 2s)

 Therefore, 2 = 2 x 22/7 x √l/10
                  4 = 2 x 22/7 x l/g
                  4 x 7/22 x 10 = l
                   6.353 m = length of the second's pendulum