Question

Find the length of an isosceles triangle of base 6 cm and the measure of each equal side is 5 cm

Answer 1

length is already written in question

Answer 2

if you are saying to find height so,,,
let the triangle name be ABC
${ad}^{2} + {bd}^{2} = {ab}^{2} \\ {ad}^{2} + {2.5}^{2} = {6}^{2} \\ {ad}^{2} + 6.25 = 36 \\ {ad}^{2} = 36 - 6.25 \\ {ad}^{2} = 36.75 \\ ad = \sqrt{36.75} \\ ad = 5.54526825320471$
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$pls \: mark \: as \: brainlist...............$
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