Question

A man can swim at 4 metre per second in a still water swimming pools he enters a 200 m wide river at one bank and swims at an angle of 60° to the river flow velocity the river flow velocity is 5 m per second in how much time does he was the river calculated drift

Answer 1

"Given, the velocity of the swimmer $v_1 = 4.0 \frac { m }{ s }$

The velocity of the river, $v_2 = 5.0 \frac { m }{ s }$

The angle between the river and the swimmer,$\theta = 60 degree$

Velocity of the swimmer towards the river bank $v = v_1sin \theta$

Time to cross the river of width 200 m $t=\frac { 200 }{ v_{ 1 }sin\theta }$

                                                              $=\frac { 200 }{ 4\times sin60 }$

                                                              $=\frac { 200 }{ 4\times \frac { \sqrt { 3 }  }{ 2 } }$

                                                               $=\frac { 200\times 2 }{ 4\times \sqrt { 3 } }$

                                                            $=\frac { 100 }{ \sqrt { 3 } }$

                                                            T = 57.735"

Answer 2

Answer:

100/√3 seconds is the time taken