Question

The sides of a triangle are P,P+1 ,2 p-1 and its area is 2p root 10 what is what is the well what is the value of p

Answer 1

The Above answer is wrong ....
....The correct answer is...
Since,
Sides of triangle are... = P , P+1 , 2P-1
therefore
S ={ P + (P+1)+(2P-1) } / 2
S = 2P
THEREFORE AREA OF TRIANGLE BY
HERONS FORMULA....
AREA =
$\sqrt{2p \: \times {2p - p} \: \times {2p - {p + 1}} \times {2p - {2p - 1}}}$
$2p \sqrt{10 \:} \: = \sqrt{2p \times p \times (p - 1)}$
$2p \sqrt{10} = \sqrt{2{p}^{2}(p - 1) }$
$2p \sqrt{10} = p \sqrt{2(p - 1)}$
SQUARING BOTH SIDES
$40 {p}^{2} = {p}^{2} \times 2(p - 1)$
$40 = 2(p - 1)$
$40 = 2p - 2$
$42 = 2p$
$therefore \: p = 21$
HOPE IT HELPS....
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Answer 2

Answer:

ok markme as brainliest