Question

find the length of latus rectum of the equation

Answer 1

It is right........ Please comment...

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Latus\:rectum(LL')=64\:units}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green {\underline \bold{Given : }} \\ \tt{ : \implies Eqn \: of \: parabola = {x}^{2} =-64y+32} \\ \\ \red {\underline \bold{to \: find: }} \\ \tt {: \implies Length \: of \: latus \: rectum (LL')=?}$

• According to given question :

$\tt{: \implies {x}^{2} = -64y+32} \\ \\ \tt{: \implies {x}^{2} = -64(y-\frac{1}{2})} \\ \\ \tt {: \implies {x}^{2} = -4\times 16 (y-\frac{1}{2} )} \\ \\ \text{So, \: it \: is \: in \: the \: form \: of} \\ \tt{: \implies X^{2} = -4bY} \\ \\ \bold{Where :} \\ \tt{\circ \: b= 16} \\ \\ \bold{As \: we \: know \: that} \\ \tt{: \implies Latus \: rectum = 4b}\\\\ \tt{:\implies Latus\:rectum=4\times 16} \\\\ \green{\tt{: \implies Latus \: rectum = 64 \: units}}$