Find the length of rectangle whose perimeter and width are perimeter=128cm and width=25cm
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Answered by
5
let the length be x
l+b= perimeter
x + 25 = 128
x = 128-25
x= 103 cm
l+b= perimeter
x + 25 = 128
x = 128-25
x= 103 cm
Anonymous:
It's answer is32
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Answered by
0
perimeter of rectangle=2(l+b)
128= 2(l+25)
128= 2l+50
128-50= 2l
70=2l
70/2=l
35=l
length of rectangle=35cm
128= 2(l+25)
128= 2l+50
128-50= 2l
70=2l
70/2=l
35=l
length of rectangle=35cm
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